rename OLDNAME,NEWNAME
Changes the name of a file; an existing file NEWNAME
will be
clobbered. Returns true for success, false otherwise.
好像是newname不能是已经存在的文件名
btw，既然用了File::Copy，为啥还要用rename
NAME
File::Copy - Copy files or filehandles
SYNOPSIS
use File::Copy;
copy("file1","file2") or die "Copy failed: $!";
copy("Copy.pm",\*STDOUT);
move("/dev1/fileA","/dev2/fileB");
use File::Copy "cp";
$n = FileHandle->new("/a/file","r");
cp($n,"x");
On 11月16日, 下午3时17分, earthminator <naz...@163.com> wrote:
> 在Linux中编写一个程序，目的是从mol文件夹中调取文件到operation文件夹中运行，再把结果传到result文件中。因为
> dssmol.exe只能运行input.mol的文件，所以要把它改名。比且运行结果是一个output文件，然后要把它在给名放到result文件
> 夹中。于是我编写如下程序：
> #!/usr/bin/perl
>
> use Cwd;
> use File::Path;
> use Shell;
> use File::Copy;
>
> $home_dir = cwd;
> $mol_dir = $home_dir .'/mols';
> $operation_dir = $home_dir .'/operation';
> $result_dir = $home_dir.'/result';
> chair ($mol_dir); #change to molecules directory
> @mol = glob ('*.mol'); #get all molecules files
> $mol_num = @mol;
> print "Total @mol_num molecules.\n";
> $i=0;
> while ($i<$mol_num) {
> print "mol_num[$i]";
> rename ("mol_num[$i] , input.mol")||die $!;
> move "input.mol , /home_dir/operation";
> system "rm -rf $input.mol";
> chair($operation_dir); #begin to run MODEL under this directory
> system " ./dssmol.exe";
> move "output , /home_dir/result/";
> system "rm -rf $input.mol";
> system "rm -rf $output";
> chair($result_dir); #change to result directory
> rename ("output , $i")||die $!;
> system "rm -rf $output";
>
> i++};
> 在运行后出现的问题是
> Not enough arguments for rename at mol1.pl line 22, near ""mol_num
> [$i] , input.mol")"
> Not enough arguments for rename at mol1.pl line 31, near ""output ,
> $i")"
> Execution of mol1.pl aborted due to compilation errors.
>
> 由于刚学perl，我不知道怎么处理这个问题。。。
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